0235
18-11-2022
THE VERTICES OF A TETRAHEDRON
Leo Vroegindeweij
Visual Artist

DETERMINATION OF THE THREE VERTICES OF THE BASE OF A REGULAR TETRAHEDRON, OF WHICH THE EARTH’S SURFACE FORMS THE CIRCUMSCRIBED SPHERE, BY MEANS OF THE RECESS OF THE TOP OF THIS TETRAHEDRON IN THE CAST OF THE EARTH’S SURFACE AT THE SPOT CHOSEN FOR THIS TOP.

Earth: Circumference = 40000000 m = 6.2831853072 rad. Radius = 6366197.724 m. Tetrahedron:  Radius circumscribed sphere = 6366197.724 m. Height = 8488263.632 m. Height base to center point = 2122065.908 m. Distance axis to vertex base = 6002108.774 m. Rib = 10395957.35 m. Angle vertex – center point – vertex = 1.9106332362 rad. Arc length vertex – vertex = 12163468.96 m. Coordinates chosen vertex tetrahedron tip: NB 0.8495922700 rad, OL 0.0957965400 rad. Casting: Height = radius earth x 2^(-27) = 0.047 m. Thickness material for height coffin Vedute = 2 x 0.012 m. Length = circumference earth x 2^(-27) = 0.298 m. Thickness material for length coffin Vedute = 2 x 0.071 m. Width = circumference earth x 2^(-27) = 0.298 m. Thickness material for width coffin Vedute = 2 x 0.011 m. Ribbed portion of tetrahedron in cast out = 0.0775 m. The vertices of the base of the tetrahedron are defined by the orientation of the cutout of the top in the cast, and should be sought respectively in the northern Pacific Ocean northeast of Midway Island, in the southern Pacific Ocean off the Chilean coast northwest of Valparaíso, and in the southern Indian Ocean southwest of Île Amsterdam.

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